y^2/(y+3)=9/(y+3)

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Solution for y^2/(y+3)=9/(y+3) equation: 


D( y )

y+3 = 0

y+3 = 0

y+3 = 0

y+3 = 0 // - 3

y = -3

y in (-oo:-3) U (-3:+oo)

(y^2)/(y+3) = 9/(y+3) // - 9/(y+3)

(y^2)/(y+3)-(9/(y+3)) = 0

(y^2)/(y+3)-9*(y+3)^-1 = 0

(y^2)/(y+3)-9/(y+3) = 0

y^2-9 = 0

(y^2-9)/(y+3) = 0

(y^2-9)/(y+3) = 0 // * y+3

y^2-9 = 0

1*y^2 = 9 // : 1

y^2 = 9

y^2 = 9 // ^ 1/2

abs(y) = 3

y = 3 or y = -3

y in { -3} 

y = 3

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